What is the general solution for sin(θ)= 20/29 ?

The general solution for sin(θ)= 20/29 is θ=0.76101…+2pin,θ=pi-0.76101…+2pin

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sin(θ)= 20/29

sin (θ) = \frac{20}{29}

θ = 0.76101 \dots + 2 πn, θ = π - 0.76101 \dots + 2 πn

Degrees

θ = 43.60281 \dots^{\circ} + 36 0^{\circ} n, θ = 136.39718 \dots^{\circ} + 36 0^{\circ} n

Solution steps

sin (θ) = \frac{20}{29}

Apply trig inverse properties

sin (θ) = \frac{20}{29}

General solutions for

sin (θ) = \frac{20}{29}

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π - arcsin (a) + 2 πn

θ = arcsin (\frac{20}{29}) + 2 πn, θ = π - arcsin (\frac{20}{29}) + 2 πn

θ = arcsin (\frac{20}{29}) + 2 πn, θ = π - arcsin (\frac{20}{29}) + 2 πn

Show solutions in decimal form

θ = 0.76101 \dots + 2 πn, θ = π - 0.76101 \dots + 2 πn

2 cos (\frac{1}{2} x) - 3 = 0

4 cos (θ) = 2

20 cos^{6} (x) - 57 cos^{4} (x) + 27 cos^{2} (x) = 0

2 sin^{2} (w) - 3 sin (w) + 1 = 0

2 + sin (x) = 5 sin (x)

What is the general solution for sin(θ)= 20/29 ?
The general solution for sin(θ)= 20/29 is θ=0.76101…+2pin,θ=pi-0.76101…+2pin