What is the general solution for 4cos(θ)=2 ?

The general solution for 4cos(θ)=2 is θ= pi/3+2pin,θ=(5pi)/3+2pin

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4cos(θ)=2

4 cos (θ) = 2

θ = \frac{π}{3} + 2 πn, θ = \frac{5 π}{3} + 2 πn

Solution steps

4 cos (θ) = 2

Divide both sides by

4

cos (θ) = \frac{1}{2}

General solutions for

cos (θ) = \frac{1}{2}

θ = \frac{π}{3} + 2 πn, θ = \frac{5 π}{3} + 2 πn

20 cos^{6} (x) - 57 cos^{4} (x) + 27 cos^{2} (x) = 0

2 sin^{2} (w) - 3 sin (w) + 1 = 0

2 + sin (x) = 5 sin (x)

2 cos (θ) + 5 = 0

sin (x) cos (x) = cos (x)

What is the general solution for 4cos(θ)=2 ?
The general solution for 4cos(θ)=2 is θ= pi/3+2pin,θ=(5pi)/3+2pin