What is the general solution for tan^2(θ)+5tan(θ)=0 ?

The general solution for tan^2(θ)+5tan(θ)=0 is θ=pin,θ=-1.37340…+pin

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tan^2(θ)+5tan(θ)=0

tan^{2} (θ) + 5 tan (θ) = 0

θ = πn, θ = - 1.37340 \dots + πn

Solution steps

tan^{2} (θ) + 5 tan (θ) = 0

Solve by substitution

tan (θ) = 0, tan (θ) = - 5

tan (θ) = 0 : θ = πn

tan (θ) = - 5 : θ = arctan (- 5) + πn

Combine all the solutions

θ = πn, θ = arctan (- 5) + πn

Show solutions in decimal form

θ = πn, θ = - 1.37340 \dots + πn

sin (4 x) - sin (6 x) = 0

2 = sec (x) + sec^{2} (x)

4 cos (θ) - 5 = 0

cos (u) = - \frac{24}{25}

4 sin (y) = \frac{1}{cos ( y )}

What is the general solution for tan^2(θ)+5tan(θ)=0 ?
The general solution for tan^2(θ)+5tan(θ)=0 is θ=pin,θ=-1.37340…+pin