What is the general solution for 2cot(x)-tan(x)+6=8-tan(x) ?

The general solution for 2cot(x)-tan(x)+6=8-tan(x) is x= pi/4+pin

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2cot(x)-tan(x)+6=8-tan(x)

2 cot (x) - tan (x) + 6 = 8 - tan (x)

x = \frac{π}{4} + πn

Solution steps

2 cot (x) - tan (x) + 6 = 8 - tan (x)

Subtract

8 - tan (x)

from both sides

2 cot (x) - 2 = 0

Move

2

to the right side

2 cot (x) = 2

Divide both sides by

2

cot (x) = 1

General solutions for

cot (x) = 1

x = \frac{π}{4} + πn

x, 2 sin (x) + 1 = 0

8 tan (3 x) = 8

1 = sin (θ) - cos (θ)

2 - cos (θ) = 2 sin^{2} (θ)

tan (2 x - \frac{π}{6}) = 1, 0 \leq x \leq 2 π

What is the general solution for 2cot(x)-tan(x)+6=8-tan(x) ?
The general solution for 2cot(x)-tan(x)+6=8-tan(x) is x= pi/4+pin