What is the general solution for cos(8x)-cos(4x)=0 ?

The general solution for cos(8x)-cos(4x)=0 is x=pin,x= pi/2+pin,x=(pin)/3 ,x= pi/6+(pin)/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

cos(8x)-cos(4x)=0

cos (8 x) - cos (4 x) = 0

x = πn, x = \frac{π}{2} + πn, x = \frac{πn}{3}, x = \frac{π}{6} + \frac{πn}{3}

Solution steps

cos (8 x) - cos (4 x) = 0

Rewrite using trig identities

- 2 sin (2 x) sin (6 x) = 0

Solving each part separately

sin (2 x) = 0 or sin (6 x) = 0

sin (2 x) = 0 : x = πn, x = \frac{π}{2} + πn

sin (6 x) = 0 : x = \frac{πn}{3}, x = \frac{π}{6} + \frac{πn}{3}

Combine all the solutions

x = πn, x = \frac{π}{2} + πn, x = \frac{πn}{3}, x = \frac{π}{6} + \frac{πn}{3}

cos (x) = \frac{4}{3}

cos^{2} (θ) - sin (θ) cos (θ) = 0

x, cos (2 x) + cos (x) = 0

2 sin (θ) + cos (2 θ) = 1

sin (π t) = 0

What is the general solution for cos(8x)-cos(4x)=0 ?
The general solution for cos(8x)-cos(4x)=0 is x=pin,x= pi/2+pin,x=(pin)/3 ,x= pi/6+(pin)/3