What is the general solution for 2sin(4x)-sqrt(3)=0 ?

The general solution for 2sin(4x)-sqrt(3)=0 is x= pi/(12)+(pin)/2 ,x= pi/6+(pin)/2

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2sin(4x)-sqrt(3)=0

2 sin (4 x) - 3 = 0

x = \frac{π}{12} + \frac{πn}{2}, x = \frac{π}{6} + \frac{πn}{2}

Solution steps

2 sin (4 x) - 3 = 0

Move

3

to the right side

2 sin (4 x) = 3

Divide both sides by

2

sin (4 x) = \frac{3}{2}

General solutions for

sin (4 x) = \frac{3}{2}

4 x = \frac{π}{3} + 2 πn, 4 x = \frac{2 π}{3} + 2 πn

Solve

4 x = \frac{π}{3} + 2 πn : x = \frac{π}{12} + \frac{πn}{2}

Solve

4 x = \frac{2 π}{3} + 2 πn : x = \frac{π}{6} + \frac{πn}{2}

x = \frac{π}{12} + \frac{πn}{2}, x = \frac{π}{6} + \frac{πn}{2}

cos (4 x) = \frac{1}{2}, 0 \leq x \leq 2 π

2 cos^{2} (t) + 3 cos (t) - 5 = 0

6 cos^{2} (x) + 7 sin (x) - 8 = 0

3 csc (x) = 2

4 csc^{2} (x) - 25 = 0

What is the general solution for 2sin(4x)-sqrt(3)=0 ?
The general solution for 2sin(4x)-sqrt(3)=0 is x= pi/(12)+(pin)/2 ,x= pi/6+(pin)/2