What is the general solution for 6cot(θ)-5=0 ?

The general solution for 6cot(θ)-5=0 is θ=0.87605…+pin

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6cot(θ)-5=0

6 cot (θ) - 5 = 0

θ = 0.87605 \dots + πn

Solution steps

6 cot (θ) - 5 = 0

Move

5

to the right side

6 cot (θ) = 5

Divide both sides by

6

cot (θ) = \frac{5}{6}

Apply trig inverse properties

θ = arccot (\frac{5}{6}) + πn

Show solutions in decimal form

θ = 0.87605 \dots + πn

8 cos (x) - 8 sin (x) = 0

sin (4 x) cos (x) - sin (x) cos (4 x) = \frac{1}{2}

arccos (x) = \frac{1}{2}

3 sin^{2} (θ) - 7 sin (θ) + 2 = 0

9 sin^{2} (θ) + 14 cos (θ) - 12 = 5 cos (θ) - 1

What is the general solution for 6cot(θ)-5=0 ?
The general solution for 6cot(θ)-5=0 is θ=0.87605…+pin