What is the general solution for 0=2+4sin(θ) ?

The general solution for 0=2+4sin(θ) is θ=(7pi)/6+2pin,θ=(11pi)/6+2pin

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0=2+4sin(θ)

0 = 2 + 4 sin (θ)

θ = \frac{7 π}{6} + 2 πn, θ = \frac{11 π}{6} + 2 πn

Solution steps

0 = 2 + 4 sin (θ)

Switch sides

2 + 4 sin (θ) = 0

Move

2

to the right side

4 sin (θ) = - 2

Divide both sides by

4

sin (θ) = - \frac{1}{2}

General solutions for

sin (θ) = - \frac{1}{2}

θ = \frac{7 π}{6} + 2 πn, θ = \frac{11 π}{6} + 2 πn

cos (x) = \frac{71}{81}

2 sin^{2} (2 x) - sin (2 x) - 3 = 0

cos (π + x) + cos (π + x) = 1

1 + 2 sin (θ) = 0

x, z = arcsin (x y)

What is the general solution for 0=2+4sin(θ) ?
The general solution for 0=2+4sin(θ) is θ=(7pi)/6+2pin,θ=(11pi)/6+2pin