What is the general solution for cos(θ)=(sqrt(11))/6 ?

The general solution for cos(θ)=(sqrt(11))/6 is θ=0.98511…+2pin,θ=2pi-0.98511…+2pin

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cos(θ)=(sqrt(11))/6

cos (θ) = \frac{11}{6}

θ = 0.98511 \dots + 2 πn, θ = 2 π - 0.98511 \dots + 2 πn

Solution steps

cos (θ) = \frac{11}{6}

Apply trig inverse properties

θ = arccos (\frac{11}{6}) + 2 πn, θ = 2 π - arccos (\frac{11}{6}) + 2 πn

Show solutions in decimal form

θ = 0.98511 \dots + 2 πn, θ = 2 π - 0.98511 \dots + 2 πn

1 + cos (x) = 3 cos (x)

2 cot (θ) + 1 = 0

tan (4 x) + 1 = 0

tan^{2} (x) - 3 = 0, 0 \leq x \leq 2 π

4 sin (θ) + 22 = 0

What is the general solution for cos(θ)=(sqrt(11))/6 ?
The general solution for cos(θ)=(sqrt(11))/6 is θ=0.98511…+2pin,θ=2pi-0.98511…+2pin