What is the general solution for sin(7x)=(sqrt(3))/2 ?

The general solution for sin(7x)=(sqrt(3))/2 is x= pi/(21)+(2pin)/7 ,x=(2pi}{21}+\frac{2pin)/7

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sin(7x)=(sqrt(3))/2

sin (7 x) = \frac{3}{2}

x = \frac{π}{21} + \frac{2 πn}{7}, x = \frac{2 π}{21} + \frac{2 πn}{7}

Solution steps

sin (7 x) = \frac{3}{2}

General solutions for

sin (7 x) = \frac{3}{2}

7 x = \frac{π}{3} + 2 πn, 7 x = \frac{2 π}{3} + 2 πn

Solve

7 x = \frac{π}{3} + 2 πn : x = \frac{π}{21} + \frac{2 πn}{7}

Solve

7 x = \frac{2 π}{3} + 2 πn : x = \frac{2 π}{21} + \frac{2 πn}{7}

x = \frac{π}{21} + \frac{2 πn}{7}, x = \frac{2 π}{21} + \frac{2 πn}{7}

- 1.9 sin (t) = 0.4 cos (2 t)

sin (\frac{x}{2}) = \frac{2}{2}

sin (2 t) = 1

sin^{4} (x) = sin^{2} (x)

2 sin^{2} (x) - 3 sin (x) = 0

What is the general solution for sin(7x)=(sqrt(3))/2 ?
The general solution for sin(7x)=(sqrt(3))/2 is x= pi/(21)+(2pin)/7 ,x=(2pi}{21}+\frac{2pin)/7