What is the general solution for sin^4(x)=sin^2(x) ?

The general solution for sin^4(x)=sin^2(x) is x= pi/2+2pin,x=(3pi)/2+2pin,x=2pin,x=pi+2pin

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sin^4(x)=sin^2(x)

sin^{4} (x) = sin^{2} (x)

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn, x = 2 πn, x = π + 2 πn

Solution steps

sin^{4} (x) = sin^{2} (x)

Solve by substitution

sin (x) = 1, sin (x) = - 1, sin (x) = 0

sin (x) = 1 : x = \frac{π}{2} + 2 πn

sin (x) = - 1 : x = \frac{3 π}{2} + 2 πn

sin (x) = 0 : x = 2 πn, x = π + 2 πn

Combine all the solutions

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn, x = 2 πn, x = π + 2 πn

2 sin^{2} (x) - 3 sin (x) = 0

0.32 = 0.59406 cos (x)

x, 4 cos (x) = 0

sec (3 x) = - \frac{2 3}{3}

cos (x) + (1 - cos^{2} (x)) 2 = 0

What is the general solution for sin^4(x)=sin^2(x) ?
The general solution for sin^4(x)=sin^2(x) is x= pi/2+2pin,x=(3pi)/2+2pin,x=2pin,x=pi+2pin