What is the general solution for 0.32=0.59406cos(x) ?

The general solution for 0.32=0.59406cos(x) is x=1.00194…+2pin,x=2pi-1.00194…+2pin

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0.32=0.59406cos(x)

0.32 = 0.59406 cos (x)

x = 1.00194 \dots + 2 πn, x = 2 π - 1.00194 \dots + 2 πn

Degrees

x = 57.40711 \dots^{\circ} + 36 0^{\circ} n, x = 302.59288 \dots^{\circ} + 36 0^{\circ} n

Solution steps

0.32 = 0.59406 cos (x)

Switch sides

0.59406 cos (x) = 0.32

Divide both sides by

0.59406

0.59406 cos (x) = 0.32

Divide both sides by

0.59406

\frac{0.59406 cos ( x )}{0.59406} = \frac{0.32}{0.59406}

Simplify

cos (x) = \frac{0.32}{0.59406}

cos (x) = \frac{0.32}{0.59406}

Apply trig inverse properties

cos (x) = \frac{0.32}{0.59406}

General solutions for

cos (x) = \frac{0.32}{0.59406}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

x = arccos (\frac{0.32}{0.59406}) + 2 πn, x = 2 π - arccos (\frac{0.32}{0.59406}) + 2 πn

x = arccos (\frac{0.32}{0.59406}) + 2 πn, x = 2 π - arccos (\frac{0.32}{0.59406}) + 2 πn

Show solutions in decimal form

x = 1.00194 \dots + 2 πn, x = 2 π - 1.00194 \dots + 2 πn

x, 4 cos (x) = 0

sec (3 x) = - \frac{2 3}{3}

cos (x) + (1 - cos^{2} (x)) 2 = 0

2 cos (3 θ) = 0

3 sin (x) + tan (x) = 0

What is the general solution for 0.32=0.59406cos(x) ?
The general solution for 0.32=0.59406cos(x) is x=1.00194…+2pin,x=2pi-1.00194…+2pin