What is the general solution for sin(b)=0.4809 ?

The general solution for sin(b)=0.4809 is b=0.50168…+2pin,b=pi-0.50168…+2pin

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sin(b)=0.4809

sin (b) = 0.4809

b = 0.50168 \dots + 2 πn, b = π - 0.50168 \dots + 2 πn

Solution steps

sin (b) = 0.4809

Apply trig inverse properties

b = arcsin (0.4809) + 2 πn, b = π - arcsin (0.4809) + 2 πn

Show solutions in decimal form

b = 0.50168 \dots + 2 πn, b = π - 0.50168 \dots + 2 πn

cos^{2} (x) - \frac{3}{4} = 0, 0 \leq x \leq 2 π

sin^{2} (x) - sin (x) - cos^{2} (x) = 0

12 cos^{2} (x) + sin (x) - 6 = 0

sin (A) = \frac{3}{5}

tan (θ) = 0.2

What is the general solution for sin(b)=0.4809 ?
The general solution for sin(b)=0.4809 is b=0.50168…+2pin,b=pi-0.50168…+2pin