What is the general solution for sin(2x+pi/4)=(sqrt(2))/2 ?

The general solution for sin(2x+pi/4)=(sqrt(2))/2 is x=pin,x=pin+pi/4

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sin(2x+pi/4)=(sqrt(2))/2

sin (2 x + \frac{π}{4}) = \frac{2}{2}

x = πn, x = πn + \frac{π}{4}

Solution steps

sin (2 x + \frac{π}{4}) = \frac{2}{2}

General solutions for

sin (2 x + \frac{π}{4}) = \frac{2}{2}

2 x + \frac{π}{4} = \frac{π}{4} + 2 πn, 2 x + \frac{π}{4} = \frac{3 π}{4} + 2 πn

Solve

2 x + \frac{π}{4} = \frac{π}{4} + 2 πn : x = πn

Solve

2 x + \frac{π}{4} = \frac{3 π}{4} + 2 πn : x = πn + \frac{π}{4}

x = πn, x = πn + \frac{π}{4}

cot (θ) = \frac{2}{3}

sec (θ) = \frac{6}{5}

3 cos (x) + 4 sin (x) = 0

0 = 2 sin (θ)

sin (\frac{π}{2} + x) = - cot (x)

What is the general solution for sin(2x+pi/4)=(sqrt(2))/2 ?
The general solution for sin(2x+pi/4)=(sqrt(2))/2 is x=pin,x=pin+pi/4