What is the general solution for sin(x+1)=0 ?

The general solution for sin(x+1)=0 is x=2pin-1,x=pi+2pin-1

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sin(x+1)=0

sin (x + 1) = 0

x = 2 πn - 1, x = π + 2 πn - 1

Solution steps

sin (x + 1) = 0

General solutions for

sin (x + 1) = 0

x + 1 = 0 + 2 πn, x + 1 = π + 2 πn

Solve

x + 1 = 0 + 2 πn : x = 2 πn - 1

Solve

x + 1 = π + 2 πn : x = π + 2 πn - 1

x = 2 πn - 1, x = π + 2 πn - 1

2 cos (\frac{2 x}{3}) + 3 = 0

sin^{2} (x) - 7 cos (x) - 7 = 0

3 sin^{2} (x) = sin (x)

2 cos (2 θ) - 3 cos (θ) + 12 = 5 cos (θ) + 7

sin (4 x) - sin (x) = 0

What is the general solution for sin(x+1)=0 ?
The general solution for sin(x+1)=0 is x=2pin-1,x=pi+2pin-1