What is the general solution for 2sin(5θ)=0 ?

The general solution for 2sin(5θ)=0 is θ=(2pin)/5 ,θ= pi/5+(2pin)/5

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2sin(5θ)=0

2 sin (5 θ) = 0

θ = \frac{2 πn}{5}, θ = \frac{π}{5} + \frac{2 πn}{5}

Solution steps

2 sin (5 θ) = 0

Divide both sides by

2

sin (5 θ) = 0

General solutions for

sin (5 θ) = 0

5 θ = 0 + 2 πn, 5 θ = π + 2 πn

Solve

5 θ = 0 + 2 πn : θ = \frac{2 πn}{5}

Solve

5 θ = π + 2 πn : θ = \frac{π}{5} + \frac{2 πn}{5}

θ = \frac{2 πn}{5}, θ = \frac{π}{5} + \frac{2 πn}{5}

x, sin^{2} (x) = 1

tan^{4} (x) - 2 = tan^{2} (x) + sec^{2} (x)

cos (x - \frac{π}{4}) = - sin (x)

sin (x) = \frac{5}{13}, cos (x)

tan (θ) = \frac{11.9}{10}

What is the general solution for 2sin(5θ)=0 ?
The general solution for 2sin(5θ)=0 is θ=(2pin)/5 ,θ= pi/5+(2pin)/5