What is the general solution for tan(2θ)=-sqrt(3) ?

The general solution for tan(2θ)=-sqrt(3) is θ= pi/3+(pin)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tan(2θ)=-sqrt(3)

tan (2 θ) = - 3

θ = \frac{π}{3} + \frac{πn}{2}

Solution steps

tan (2 θ) = - 3

General solutions for

tan (2 θ) = - 3

2 θ = \frac{2 π}{3} + πn

Solve

2 θ = \frac{2 π}{3} + πn : θ = \frac{π}{3} + \frac{πn}{2}

θ = \frac{π}{3} + \frac{πn}{2}

sin (x) + cos (x) = \frac{2}{5}

2 cos (x) + 2 sin (x) cos (x) = 0

100 cos (3 0^{\circ}) - 200 cos (θ) = 0

x, y = sin (2 x + 3 y)

cos (θ) = \frac{8}{9}

What is the general solution for tan(2θ)=-sqrt(3) ?
The general solution for tan(2θ)=-sqrt(3) is θ= pi/3+(pin)/2