What is the general solution for -5cos(5x)=0 ?

The general solution for -5cos(5x)=0 is x= pi/(10)+(2pin)/5 ,x=(3pi}{10}+\frac{2pin)/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

-5cos(5x)=0

- 5 cos (5 x) = 0

x = \frac{π}{10} + \frac{2 πn}{5}, x = \frac{3 π}{10} + \frac{2 πn}{5}

Solution steps

- 5 cos (5 x) = 0

Divide both sides by

- 5

cos (5 x) = 0

General solutions for

cos (5 x) = 0

5 x = \frac{π}{2} + 2 πn, 5 x = \frac{3 π}{2} + 2 πn

Solve

5 x = \frac{π}{2} + 2 πn : x = \frac{π}{10} + \frac{2 πn}{5}

Solve

5 x = \frac{3 π}{2} + 2 πn : x = \frac{3 π}{10} + \frac{2 πn}{5}

x = \frac{π}{10} + \frac{2 πn}{5}, x = \frac{3 π}{10} + \frac{2 πn}{5}

2 sin (x) tan (x) + 5 = 4 sec (x)

cos^{2} (x) - cos (x) - 2 = 0, 0 \leq x \leq 2 π

cos^{4} (x) - 1 = 0

sec (x) - cos (x) = sin (x)

2 sin (x) = 3, 0 \leq x < 2 π

What is the general solution for -5cos(5x)=0 ?
The general solution for -5cos(5x)=0 is x= pi/(10)+(2pin)/5 ,x=(3pi}{10}+\frac{2pin)/5