What is the general solution for 6sin(θ)+6=0 ?

The general solution for 6sin(θ)+6=0 is θ=(3pi)/2+2pin

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6sin(θ)+6=0

6 sin (θ) + 6 = 0

θ = \frac{3 π}{2} + 2 πn

Solution steps

6 sin (θ) + 6 = 0

Move

6

to the right side

6 sin (θ) = - 6

Divide both sides by

6

sin (θ) = - 1

General solutions for

sin (θ) = - 1

θ = \frac{3 π}{2} + 2 πn

cosh (z) = - 2

tan (\frac{θ}{2} + \frac{π}{3}) = - 1, 0 \leq θ < 2 π

- 9 cos^{2} (θ) + 13 = 20 sin (θ)

0 = sin (3 θ)

sec (θ) = \frac{1}{sin ( θ )}

What is the general solution for 6sin(θ)+6=0 ?
The general solution for 6sin(θ)+6=0 is θ=(3pi)/2+2pin