What is the general solution for tan^2(3t+pi/2)= 1/3 ?

The general solution for tan^2(3t+pi/2)= 1/3 is t=(pin)/3-pi/9 ,t=(pin)/3-(2pi)/9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tan^2(3t+pi/2)= 1/3

tan^{2} (3 t + \frac{π}{2}) = \frac{1}{3}

t = \frac{πn}{3} - \frac{π}{9}, t = \frac{πn}{3} - \frac{2 π}{9}

Solution steps

tan^{2} (3 t + \frac{π}{2}) = \frac{1}{3}

Solve by substitution

tan (3 t + \frac{π}{2}) = \frac{1}{3}, tan (3 t + \frac{π}{2}) = - \frac{1}{3}

tan (3 t + \frac{π}{2}) = \frac{1}{3} : t = \frac{πn}{3} - \frac{π}{9}

tan (3 t + \frac{π}{2}) = - \frac{1}{3} : t = \frac{πn}{3} - \frac{2 π}{9}

Combine all the solutions

t = \frac{πn}{3} - \frac{π}{9}, t = \frac{πn}{3} - \frac{2 π}{9}

0 = - 2 sin (2 x)

2 sin^{2} (θ) - 7 sin (θ) + 5 = 0

x, 4 cos^{2} (x) - 3 = 0

tan (x) = \frac{2}{4}

2 sin^{2} (t) - cos (t) = 1

What is the general solution for tan^2(3t+pi/2)= 1/3 ?
The general solution for tan^2(3t+pi/2)= 1/3 is t=(pin)/3-pi/9 ,t=(pin)/3-(2pi)/9