What is the general solution for 0=-2sin(2x) ?

The general solution for 0=-2sin(2x) is x=pin,x= pi/2+pin

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0=-2sin(2x)

0 = - 2 sin (2 x)

x = πn, x = \frac{π}{2} + πn

Solution steps

0 = - 2 sin (2 x)

Switch sides

- 2 sin (2 x) = 0

Divide both sides by

- 2

sin (2 x) = 0

General solutions for

sin (2 x) = 0

2 x = 0 + 2 πn, 2 x = π + 2 πn

Solve

2 x = 0 + 2 πn : x = πn

Solve

2 x = π + 2 πn : x = \frac{π}{2} + πn

x = πn, x = \frac{π}{2} + πn

2 sin^{2} (θ) - 7 sin (θ) + 5 = 0

x, 4 cos^{2} (x) - 3 = 0

tan (x) = \frac{2}{4}

2 sin^{2} (t) - cos (t) = 1

4 sin^{2} (x) + 4 sin (x) = - 1

What is the general solution for 0=-2sin(2x) ?
The general solution for 0=-2sin(2x) is x=pin,x= pi/2+pin