What is the general solution for sin(1/x)=0,5 ?

The general solution for sin(1/x)=0,5 is No Solution for x\in\mathbb{R};\quad n\ne 0,n\ne-1/2

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sin(1/x)=0,5

sin (\frac{1}{x}) = 0, 5

No Solution for x \in R; n \neq = 0, n \neq = - \frac{1}{2}

Solution steps

sin (\frac{1}{x}) = 0, 5

General solutions for

sin (\frac{1}{x}) = 0

\frac{1}{x} = 0 + 2 πn, \frac{1}{x} = π + 2 πn

Solve

\frac{1}{x} = 0 + 2 πn : x = \frac{1}{2 πn}; n \neq = 0

Solve

\frac{1}{x} = π + 2 πn : x = \frac{1}{π ( 1 + 2 n )}; n \neq = - \frac{1}{2}

x = \frac{1}{2 πn}, x = \frac{1}{π ( 1 + 2 n )}; n \neq = 0, n \neq = - \frac{1}{2}

Solutions for the range

5

No Solution for x \in R; n \neq = 0, n \neq = - \frac{1}{2}

tan (2 x) sin (x) = sin (x)

sin (u) = - \frac{3}{5}, \frac{3 π}{2} < u < 2 π

2 - 2 sin^{2} (\frac{x}{2}) = sin^{2} (x)

sin (x) + cos (x) = 2

3 cos (B) - 1 = 5 cos (B) + 1

What is the general solution for sin(1/x)=0,5 ?
The general solution for sin(1/x)=0,5 is No Solution for x\in\mathbb{R};\quad n\ne 0,n\ne-1/2