What is the general solution for 3cos(B)-1=5cos(B)+1 ?

The general solution for 3cos(B)-1=5cos(B)+1 is B=pi+2pin

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3cos(B)-1=5cos(B)+1

3 cos (B) - 1 = 5 cos (B) + 1

B = π + 2 πn

Solution steps

3 cos (B) - 1 = 5 cos (B) + 1

Solve by substitution

cos (B) = - 1

cos (B) = - 1 : B = π + 2 πn

Combine all the solutions

B = π + 2 πn

cos (θ) = \frac{3}{4}

cos (x) = \frac{- 3}{5}

x, sin (2 x) = - \frac{1}{2}

9 cos (2 θ) = 27 cos (θ) - 18

4 csc (x) = 3 csc (x) cot (x) + 3 csc (x)

What is the general solution for 3cos(B)-1=5cos(B)+1 ?
The general solution for 3cos(B)-1=5cos(B)+1 is B=pi+2pin