What is the general solution for solvefor x,p+3q=z+cot(y-3x) ?

The general solution for solvefor x,p+3q=z+cot(y-3x) is x=-(arccot(p+3q-z))/3-(pin)/3+y/3

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solvefor x,p+3q=z+cot(y-3x)

solve for

x, p + 3 q = z + cot (y - 3 x)

x = - \frac{arccot ( p + 3 q - z )}{3} - \frac{πn}{3} + \frac{y}{3}

Solution steps

p + 3 q = z + cot (y - 3 x)

Switch sides

z + cot (y - 3 x) = p + 3 q

Move

z

to the right side

cot (y - 3 x) = p + 3 q - z

Apply trig inverse properties

y - 3 x = arccot (p + 3 q - z) + πn

Solve

y - 3 x = arccot (p + 3 q - z) + πn : x = - \frac{arccot ( p + 3 q - z )}{3} - \frac{πn}{3} + \frac{y}{3}

x = - \frac{arccot ( p + 3 q - z )}{3} - \frac{πn}{3} + \frac{y}{3}

4 sin (x) cos (x) = 0

sin (2 x) sin (x) = 0, 0^{\circ} \leq x \leq 36 0^{\circ}

cot^{2} (x) = csc (x) + 1

cos (x) - sin (x) = 0.5

sin (x + π) - sin (x) + 3 = 0

What is the general solution for solvefor x,p+3q=z+cot(y-3x) ?
The general solution for solvefor x,p+3q=z+cot(y-3x) is x=-(arccot(p+3q-z))/3-(pin)/3+y/3