What is the general solution for sin(x)= 1/2 ,0<= x<2pi ?

The general solution for sin(x)= 1/2 ,0<= x<2pi is x= pi/6 ,x=(5pi)/6

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sin(x)= 1/2 ,0<= x<2pi

sin (x) = \frac{1}{2}, 0 \leq x < 2 π

x = \frac{π}{6}, x = \frac{5 π}{6}

Solution steps

sin (x) = \frac{1}{2}, 0 \leq x < 2 π

General solutions for

sin (x) = \frac{1}{2}

x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

Solutions for the range

0 \leq x < 2 π

x = \frac{π}{6}, x = \frac{5 π}{6}

cos (t) + cos (2 t) = - 1

sin (θ) = \frac{3}{4}

3 cos (t) = 0

cos (θ) = \frac{7}{9}

1 - cot^{2} (x) = 0

What is the general solution for sin(x)= 1/2 ,0<= x<2pi ?
The general solution for sin(x)= 1/2 ,0<= x<2pi is x= pi/6 ,x=(5pi)/6