What is the general solution for cos(x)cot(x)cos(x)=0,0<= x<= 2pi ?

The general solution for cos(x)cot(x)cos(x)=0,0<= x<= 2pi is x= pi/2 ,x=(3pi)/2

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cos(x)cot(x)cos(x)=0,0<= x<= 2pi

cos (x) cot (x) cos (x) = 0, 0 \leq x \leq 2 π

x = \frac{π}{2}, x = \frac{3 π}{2}

Solution steps

cos (x) cot (x) cos (x) = 0, 0 \leq x \leq 2 π

Solving each part separately

cos (x) = 0 or cot (x) = 0 or cos (x) = 0

cos (x) = 0, 0 \leq x \leq 2 π : x = \frac{π}{2}, x = \frac{3 π}{2}

cot (x) = 0, 0 \leq x \leq 2 π : x = \frac{π}{2}, x = \frac{3 π}{2}

cos (x) = 0, 0 \leq x \leq 2 π : x = \frac{π}{2}, x = \frac{3 π}{2}

Combine all the solutions

x = \frac{π}{2}, x = \frac{3 π}{2}

0 = cos^{2} (x)

3 cos (θ) = - 3 sin (- θ)

3 sec (x) - 6 = 0

sin (2 x) = \frac{1}{3}

4 sin (θ) - 3 = 2 sin (θ)

What is the general solution for cos(x)cot(x)cos(x)=0,0<= x<= 2pi ?
The general solution for cos(x)cot(x)cos(x)=0,0<= x<= 2pi is x= pi/2 ,x=(3pi)/2