What is the general solution for 2sin(3θ)=sqrt(3) ?

The general solution for 2sin(3θ)=sqrt(3) is θ= pi/9+(2pin)/3 ,θ=(2pi)/9+(2pin)/3

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2sin(3θ)=sqrt(3)

2 sin (3 θ) = 3

θ = \frac{π}{9} + \frac{2 πn}{3}, θ = \frac{2 π}{9} + \frac{2 πn}{3}

Solution steps

2 sin (3 θ) = 3

Divide both sides by

2

sin (3 θ) = \frac{3}{2}

General solutions for

sin (3 θ) = \frac{3}{2}

3 θ = \frac{π}{3} + 2 πn, 3 θ = \frac{2 π}{3} + 2 πn

Solve

3 θ = \frac{π}{3} + 2 πn : θ = \frac{π}{9} + \frac{2 πn}{3}

Solve

3 θ = \frac{2 π}{3} + 2 πn : θ = \frac{2 π}{9} + \frac{2 πn}{3}

θ = \frac{π}{9} + \frac{2 πn}{3}, θ = \frac{2 π}{9} + \frac{2 πn}{3}

sin^{2} (x) + 2 sin (x) = 3

10 (1 - cos (x)) = sin^{2} (x)

2 sin (4 x) = 0

9 \cdot csc (x) = 63, (- \infty, \infty)

cos (2 x - \frac{π}{2}) = 1

What is the general solution for 2sin(3θ)=sqrt(3) ?
The general solution for 2sin(3θ)=sqrt(3) is θ= pi/9+(2pin)/3 ,θ=(2pi)/9+(2pin)/3