What is the general solution for cos(b)=0.3125 ?

The general solution for cos(b)=0.3125 is b=1.25297…+2pin,b=2pi-1.25297…+2pin

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cos(b)=0.3125

cos (b) = 0.3125

b = 1.25297 \dots + 2 πn, b = 2 π - 1.25297 \dots + 2 πn

Solution steps

cos (b) = 0.3125

Apply trig inverse properties

b = arccos (0.3125) + 2 πn, b = 2 π - arccos (0.3125) + 2 πn

Show solutions in decimal form

b = 1.25297 \dots + 2 πn, b = 2 π - 1.25297 \dots + 2 πn

sin (\frac{1}{2} x) - 1 = 0

- \frac{1}{16} sin (\frac{x}{4}) = 0

sec (x) = - 2, π < x < \frac{3 π}{2}

sin (x) cos (x) = cos^{2} (x)

x, sin (x - y) = 0

What is the general solution for cos(b)=0.3125 ?
The general solution for cos(b)=0.3125 is b=1.25297…+2pin,b=2pi-1.25297…+2pin