What is the general solution for 2cos(θ)-2=6cos(θ) ?

The general solution for 2cos(θ)-2=6cos(θ) is θ=(2pi)/3+2pin,θ=(4pi)/3+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2cos(θ)-2=6cos(θ)

2 cos (θ) - 2 = 6 cos (θ)

θ = \frac{2 π}{3} + 2 πn, θ = \frac{4 π}{3} + 2 πn

Solution steps

2 cos (θ) - 2 = 6 cos (θ)

Solve by substitution

cos (θ) = - \frac{1}{2}

cos (θ) = - \frac{1}{2} : θ = \frac{2 π}{3} + 2 πn, θ = \frac{4 π}{3} + 2 πn

Combine all the solutions

θ = \frac{2 π}{3} + 2 πn, θ = \frac{4 π}{3} + 2 πn

10 sin^{2} (x) + 15 sin (x) + 5 = 0

3 sin (θ) - 1 = - 1

sin (x) = \frac{6.2}{8}

cos (2 θ) = \frac{3}{2}, 0 \leq θ \leq 2 π

- 2 cot (x) + 1 = 23 + 1

What is the general solution for 2cos(θ)-2=6cos(θ) ?
The general solution for 2cos(θ)-2=6cos(θ) is θ=(2pi)/3+2pin,θ=(4pi)/3+2pin