What is the general solution for 3sin(θ)-1=-1 ?

The general solution for 3sin(θ)-1=-1 is θ=2pin,θ=pi+2pin

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3sin(θ)-1=-1

3 sin (θ) - 1 = - 1

θ = 2 πn, θ = π + 2 πn

Solution steps

3 sin (θ) - 1 = - 1

Add

1

to both sides

3 sin (θ) - 1 + 1 = - 1 + 1

Simplify

3 sin (θ) = 0

Divide both sides by

3

sin (θ) = 0

General solutions for

sin (θ) = 0

θ = 0 + 2 πn, θ = π + 2 πn

Solve

θ = 0 + 2 πn : θ = 2 πn

θ = 2 πn, θ = π + 2 πn

sin (x) = \frac{6.2}{8}

cos (2 θ) = \frac{3}{2}, 0 \leq θ \leq 2 π

- 2 cot (x) + 1 = 23 + 1

32 cos (θ) + 1 = - 2, 0 \leq θ < 2 π

cos (u) = - \frac{15}{17}

What is the general solution for 3sin(θ)-1=-1 ?
The general solution for 3sin(θ)-1=-1 is θ=2pin,θ=pi+2pin