What is the general solution for tan(θ/2+pi/6)=-1,0<= θ<2pi ?

The general solution for tan(θ/2+pi/6)=-1,0<= θ<2pi is θ=(7pi)/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tan(θ/2+pi/6)=-1,0<= θ<2pi

tan (\frac{θ}{2} + \frac{π}{6}) = - 1, 0 \leq θ < 2 π

θ = \frac{7 π}{6}

Solution steps

tan (\frac{θ}{2} + \frac{π}{6}) = - 1, 0 \leq θ < 2 π

General solutions for

tan (\frac{θ}{2} + \frac{π}{6}) = - 1

\frac{θ}{2} + \frac{π}{6} = \frac{3 π}{4} + πn

Solve

\frac{θ}{2} + \frac{π}{6} = \frac{3 π}{4} + πn : θ = 2 πn + \frac{7 π}{6}

θ = 2 πn + \frac{7 π}{6}

Solutions for the range

0 \leq θ < 2 π

θ = \frac{7 π}{6}

3 sec^{2} (x) - 3 = 0

tan (θ) = 19, 0 \leq θ < 2 π

cos (2 θ) - 2 cos (θ) = - 1

(sec (x) - 2) (3 sec (x) + 2) = 0

csc (x) cot (x) = 2

What is the general solution for tan(θ/2+pi/6)=-1,0<= θ<2pi ?
The general solution for tan(θ/2+pi/6)=-1,0<= θ<2pi is θ=(7pi)/6