What is the general solution for 14sin^2(x)-7sin(x)=0 ?

The general solution for 14sin^2(x)-7sin(x)=0 is x= pi/6+2pin,x=(5pi)/6+2pin,x=2pin,x=pi+2pin

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14sin^2(x)-7sin(x)=0

14 sin^{2} (x) - 7 sin (x) = 0

x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn, x = 2 πn, x = π + 2 πn

Solution steps

14 sin^{2} (x) - 7 sin (x) = 0

Solve by substitution

sin (x) = \frac{1}{2}, sin (x) = 0

sin (x) = \frac{1}{2} : x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

sin (x) = 0 : x = 2 πn, x = π + 2 πn

Combine all the solutions

x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn, x = 2 πn, x = π + 2 πn

cos (α) = \frac{2}{3}

sec (- 2 x) = - 2

- sin (x) = \frac{1}{2}

sin (x) sec (x) = 2 sin (x), 0 \leq x \leq 2 π

3 cos^{2} (y) - 1 = cos (y) + cos^{2} (y), π \leq y \leq 2 π

What is the general solution for 14sin^2(x)-7sin(x)=0 ?
The general solution for 14sin^2(x)-7sin(x)=0 is x= pi/6+2pin,x=(5pi)/6+2pin,x=2pin,x=pi+2pin