What is the general solution for 3cos^2(y)-1=cos(y)+cos^2(y),pi<= y<= 2pi ?

The general solution for 3cos^2(y)-1=cos(y)+cos^2(y),pi<= y<= 2pi is y=2pi,y=(4pi)/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3cos^2(y)-1=cos(y)+cos^2(y),pi<= y<= 2pi

3 cos^{2} (y) - 1 = cos (y) + cos^{2} (y), π \leq y \leq 2 π

y = 2 π, y = \frac{4 π}{3}

Solution steps

3 cos^{2} (y) - 1 = cos (y) + cos^{2} (y), π \leq y \leq 2 π

Solve by substitution

cos (y) = 1, cos (y) = - \frac{1}{2}

cos (y) = 1, π \leq y \leq 2 π : y = 2 π

cos (y) = - \frac{1}{2}, π \leq y \leq 2 π : y = \frac{4 π}{3}

Combine all the solutions

y = 2 π, y = \frac{4 π}{3}

sec^{2} (x) + tan (x) = 1, 0 \leq x \leq 2 π

6 tanh^{2} (x) + 5 sech (x) - 7 = 0

2 sin (x) + 2 = 0, 0 \leq x \leq 2 π

2 cos^{2} (x) + 3 cos (x) = 2, 0 \leq x \leq 2 π

cos (θ) = \frac{7}{11}

What is the general solution for 3cos^2(y)-1=cos(y)+cos^2(y),pi<= y<= 2pi ?
The general solution for 3cos^2(y)-1=cos(y)+cos^2(y),pi<= y<= 2pi is y=2pi,y=(4pi)/3