What is the general solution for solvefor x,y-1/(cos(x))=0 ?

The general solution for solvefor x,y-1/(cos(x))=0 is x=arccos(1/y)+2pin,x=-arccos(1/y)+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor x,y-1/(cos(x))=0

solve for

x, y - \frac{1}{cos ( x )} = 0

x = arccos (\frac{1}{y}) + 2 πn, x = - arccos (\frac{1}{y}) + 2 πn

Solution steps

y - \frac{1}{cos ( x )} = 0

Multiply both sides by

cos (x)

y cos (x) - 1 = 0

Move

1

to the right side

y cos (x) = 1

Divide both sides by

y; y \neq = 0

cos (x) = \frac{1}{y}; y \neq = 0

Apply trig inverse properties

x = arccos (\frac{1}{y}) + 2 πn, x = - arccos (\frac{1}{y}) + 2 πn

2 sin (x) - cos (2 x) = 0

sin^{2} (x) sec (x) = tan^{2} (x)

cos (2 x + \frac{π}{3}) = - \frac{1}{2}

sec (θ + 2 0^{\circ}) = 3

tan (θ) = \frac{7.7}{14}

What is the general solution for solvefor x,y-1/(cos(x))=0 ?
The general solution for solvefor x,y-1/(cos(x))=0 is x=arccos(1/y)+2pin,x=-arccos(1/y)+2pin