What is the general solution for tan^2(2x)-3=0 ?

The general solution for tan^2(2x)-3=0 is x= pi/6+(pin)/2 ,x= pi/3+(pin)/2

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tan^2(2x)-3=0

tan^{2} (2 x) - 3 = 0

x = \frac{π}{6} + \frac{πn}{2}, x = \frac{π}{3} + \frac{πn}{2}

Solution steps

tan^{2} (2 x) - 3 = 0

Solve by substitution

tan (2 x) = 3, tan (2 x) = - 3

tan (2 x) = 3 : x = \frac{π}{6} + \frac{πn}{2}

tan (2 x) = - 3 : x = \frac{π}{3} + \frac{πn}{2}

Combine all the solutions

x = \frac{π}{6} + \frac{πn}{2}, x = \frac{π}{3} + \frac{πn}{2}

tan^{2} (θ) = 2 sec (θ) - 1

5 cosh (x) - 3 sinh (x) = 5

sin^{2} (x) cos (x) - cos (x) = 0

sin (2 θ) = \frac{3}{2}, 0 \leq θ \leq 2 π

- 6 sin^{2} (x) = cos (2 x) - 2

What is the general solution for tan^2(2x)-3=0 ?
The general solution for tan^2(2x)-3=0 is x= pi/6+(pin)/2 ,x= pi/3+(pin)/2