What is the general solution for -2sin(θ)=-sqrt(2) ?

The general solution for -2sin(θ)=-sqrt(2) is θ= pi/4+2pin,θ=(3pi)/4+2pin

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-2sin(θ)=-sqrt(2)

- 2 sin (θ) = - 2

θ = \frac{π}{4} + 2 πn, θ = \frac{3 π}{4} + 2 πn

Solution steps

- 2 sin (θ) = - 2

Divide both sides by

- 2

sin (θ) = \frac{2}{2}

General solutions for

sin (θ) = \frac{2}{2}

θ = \frac{π}{4} + 2 πn, θ = \frac{3 π}{4} + 2 πn

sin (x) = \frac{25}{60}

cos (x) - cos^{2} (x) = 0

tan (x) = 1.25

sin (x^{2}) = cos (x^{2})

sin (2 x - 10) = cos (x + 1 0^{\circ})

What is the general solution for -2sin(θ)=-sqrt(2) ?
The general solution for -2sin(θ)=-sqrt(2) is θ= pi/4+2pin,θ=(3pi)/4+2pin