What is the general solution for -6cos(2x)=0 ?

The general solution for -6cos(2x)=0 is x= pi/4+pin,x=(3pi)/4+pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

-6cos(2x)=0

- 6 cos (2 x) = 0

x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

Solution steps

- 6 cos (2 x) = 0

Divide both sides by

- 6

cos (2 x) = 0

General solutions for

cos (2 x) = 0

2 x = \frac{π}{2} + 2 πn, 2 x = \frac{3 π}{2} + 2 πn

Solve

2 x = \frac{π}{2} + 2 πn : x = \frac{π}{4} + πn

Solve

2 x = \frac{3 π}{2} + 2 πn : x = \frac{3 π}{4} + πn

x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

t, x = 4 cos (t)

2 cos^{3} (θ) - cos (θ) = 0

sin^{2} (x) + 3 sin (x) = - 2

- sin (π x) π = 0

cos^{2} (x) - 3 sin^{2} (x) = 1

What is the general solution for -6cos(2x)=0 ?
The general solution for -6cos(2x)=0 is x= pi/4+pin,x=(3pi)/4+pin