What is the general solution for -sin(pix)pi=0 ?

The general solution for -sin(pix)pi=0 is x=2n,x=1+2n

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

-sin(pix)pi=0

- sin (π x) π = 0

x = 2 n, x = 1 + 2 n

Solution steps

- sin (π x) π = 0

Divide both sides by

- π

sin (π x) = 0

General solutions for

sin (π x) = 0

π x = 0 + 2 πn, π x = π + 2 πn

Solve

π x = 0 + 2 πn : x = 2 n

Solve

π x = π + 2 πn : x = 1 + 2 n

x = 2 n, x = 1 + 2 n

cos^{2} (x) - 3 sin^{2} (x) = 1

sin (\frac{x}{6}) = 0

(tan (θ) - 1) (sec (θ) - 1) = 0, 0 \leq θ \leq 2 π

cos (θ) = \frac{4.4}{11}

x, cos^{3} (x) - cos (x) = 0

What is the general solution for -sin(pix)pi=0 ?
The general solution for -sin(pix)pi=0 is x=2n,x=1+2n