What is the general solution for (tan(θ)-1)(sec(θ)-1)=0,0<= θ<= 2pi ?

The general solution for (tan(θ)-1)(sec(θ)-1)=0,0<= θ<= 2pi is θ= pi/4 ,θ=(5pi)/4 ,θ=0,θ=2pi

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(tan(θ)-1)(sec(θ)-1)=0,0<= θ<= 2pi

(tan (θ) - 1) (sec (θ) - 1) = 0, 0 \leq θ \leq 2 π

θ = \frac{π}{4}, θ = \frac{5 π}{4}, θ = 0, θ = 2 π

Solution steps

(tan (θ) - 1) (sec (θ) - 1) = 0, 0 \leq θ \leq 2 π

Solving each part separately

tan (θ) - 1 = 0 or sec (θ) - 1 = 0

tan (θ) - 1 = 0, 0 \leq θ \leq 2 π : θ = \frac{π}{4}, θ = \frac{5 π}{4}

sec (θ) - 1 = 0, 0 \leq θ \leq 2 π : θ = 0, θ = 2 π

Combine all the solutions

θ = \frac{π}{4}, θ = \frac{5 π}{4}, θ = 0, θ = 2 π

cos (θ) = \frac{4.4}{11}

x, cos^{3} (x) - cos (x) = 0

- 6 sin^{2} (θ) - 3 = sin (θ) - 5

2 cos^{2} (x) = sin (x)

23 sin (2 x) - 3 = 0

What is the general solution for (tan(θ)-1)(sec(θ)-1)=0,0<= θ<= 2pi ?
The general solution for (tan(θ)-1)(sec(θ)-1)=0,0<= θ<= 2pi is θ= pi/4 ,θ=(5pi)/4 ,θ=0,θ=2pi