What is the general solution for 2sqrt(3)sin(2x)-3=0 ?

The general solution for 2sqrt(3)sin(2x)-3=0 is x= pi/6+pin,x= pi/3+pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2sqrt(3)sin(2x)-3=0

23 sin (2 x) - 3 = 0

x = \frac{π}{6} + πn, x = \frac{π}{3} + πn

Solution steps

23 sin (2 x) - 3 = 0

Move

3

to the right side

23 sin (2 x) = 3

Divide both sides by

23

sin (2 x) = \frac{3}{2}

General solutions for

sin (2 x) = \frac{3}{2}

2 x = \frac{π}{3} + 2 πn, 2 x = \frac{2 π}{3} + 2 πn

Solve

2 x = \frac{π}{3} + 2 πn : x = \frac{π}{6} + πn

Solve

2 x = \frac{2 π}{3} + 2 πn : x = \frac{π}{3} + πn

x = \frac{π}{6} + πn, x = \frac{π}{3} + πn

sec (x) = \frac{3}{2}

sin (2 x) = 3

x, cos (x + y) = 0

θ, sin (2 θ) = \frac{1}{2}

sin (x) + cos (x) = \frac{6}{2}

What is the general solution for 2sqrt(3)sin(2x)-3=0 ?
The general solution for 2sqrt(3)sin(2x)-3=0 is x= pi/6+pin,x= pi/3+pin