What is the general solution for solvefor θ,sin(2θ)= 1/2 ?

The general solution for solvefor θ,sin(2θ)= 1/2 is θ= pi/(12)+pin,θ=(5pi)/(12)+pin

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solvefor θ,sin(2θ)= 1/2

solve for

θ, sin (2 θ) = \frac{1}{2}

θ = \frac{π}{12} + πn, θ = \frac{5 π}{12} + πn

Solution steps

sin (2 θ) = \frac{1}{2}

General solutions for

sin (2 θ) = \frac{1}{2}

2 θ = \frac{π}{6} + 2 πn, 2 θ = \frac{5 π}{6} + 2 πn

Solve

2 θ = \frac{π}{6} + 2 πn : θ = \frac{π}{12} + πn

Solve

2 θ = \frac{5 π}{6} + 2 πn : θ = \frac{5 π}{12} + πn

θ = \frac{π}{12} + πn, θ = \frac{5 π}{12} + πn

sin (x) + cos (x) = \frac{6}{2}

2 cos^{2} (\frac{x}{3}) + 3 sin (\frac{x}{3}) - 3 = 0

y, cos (x) = x (1 + cot (y))

sec^{2} (x) - 3 = 0

- 4 sin (2 θ) = 0

What is the general solution for solvefor θ,sin(2θ)= 1/2 ?
The general solution for solvefor θ,sin(2θ)= 1/2 is θ= pi/(12)+pin,θ=(5pi)/(12)+pin