What is the general solution for (cot(θ)+1)(csc(θ)-1/2)=0 ?

The general solution for (cot(θ)+1)(csc(θ)-1/2)=0 is θ=(3pi)/4+pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(cot(θ)+1)(csc(θ)-1/2)=0

(cot (θ) + 1) (csc (θ) - \frac{1}{2}) = 0

θ = \frac{3 π}{4} + πn

Solution steps

(cot (θ) + 1) (csc (θ) - \frac{1}{2}) = 0

Solving each part separately

cot (θ) + 1 = 0 or csc (θ) - \frac{1}{2} = 0

cot (θ) + 1 = 0 : θ = \frac{3 π}{4} + πn

csc (θ) - \frac{1}{2} = 0 :

No Solution

Combine all the solutions

θ = \frac{3 π}{4} + πn

tan^{2} (x) = 1 + sec^{2} (x)

cos (x) = \frac{50}{86}

cos (θ) = 1.1111111

sin (5 θ) - 17 = - 18

x, z = tan (2 x - y)

What is the general solution for (cot(θ)+1)(csc(θ)-1/2)=0 ?
The general solution for (cot(θ)+1)(csc(θ)-1/2)=0 is θ=(3pi)/4+pin