What is the general solution for sqrt(3)sec(2x)+2=0 ?

The general solution for sqrt(3)sec(2x)+2=0 is x=(5pi)/(12)+pin,x=(7pi)/(12)+pin

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sqrt(3)sec(2x)+2=0

3 sec (2 x) + 2 = 0

x = \frac{5 π}{12} + πn, x = \frac{7 π}{12} + πn

Solution steps

3 sec (2 x) + 2 = 0

Move

2

to the right side

3 sec (2 x) = - 2

Divide both sides by

3

sec (2 x) = - \frac{2 3}{3}

General solutions for

sec (2 x) = - \frac{2 3}{3}

2 x = \frac{5 π}{6} + 2 πn, 2 x = \frac{7 π}{6} + 2 πn

Solve

2 x = \frac{5 π}{6} + 2 πn : x = \frac{5 π}{12} + πn

Solve

2 x = \frac{7 π}{6} + 2 πn : x = \frac{7 π}{12} + πn

x = \frac{5 π}{12} + πn, x = \frac{7 π}{12} + πn

e^{t a n (x)} - 2 = 0

32 sec (θ) + 7 = 1

cos (x) + cos^{2} (x) - sin^{2} (x) = 0

x, 2 sin (x) + csc (x) = 0

4 cos^{2} (x) + 4 = 6

What is the general solution for sqrt(3)sec(2x)+2=0 ?
The general solution for sqrt(3)sec(2x)+2=0 is x=(5pi)/(12)+pin,x=(7pi)/(12)+pin