What is the general solution for 1+sin^2(x)=cos^2(x) ?

The general solution for 1+sin^2(x)=cos^2(x) is x=pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

1+sin^2(x)=cos^2(x)

1 + sin^{2} (x) = cos^{2} (x)

x = πn

Solution steps

1 + sin^{2} (x) = cos^{2} (x)

Subtract

cos^{2} (x)

from both sides

1 + sin^{2} (x) - cos^{2} (x) = 0

Rewrite using trig identities

1 - cos (2 x) = 0

Move

1

to the right side

- cos (2 x) = - 1

Divide both sides by

- 1

cos (2 x) = 1

General solutions for

cos (2 x) = 1

2 x = 0 + 2 πn

Solve

2 x = 0 + 2 πn : x = πn

x = πn

7 tan (θ) sin (θ) - 6 tan (θ) = 0

2 sin^{2} (x) - 7 cos (x) + 2 = 0

5 cos (θ) = 0

sin (2 θ) = 4 cos (θ)

tan (θ) = \frac{4}{4}

What is the general solution for 1+sin^2(x)=cos^2(x) ?
The general solution for 1+sin^2(x)=cos^2(x) is x=pin