What is the general solution for cos(2θ)=sqrt(2)-cos(2θ) ?

The general solution for cos(2θ)=sqrt(2)-cos(2θ) is θ= pi/8+pin,θ=(7pi)/8+pin

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cos(2θ)=sqrt(2)-cos(2θ)

cos (2 θ) = 2 - cos (2 θ)

θ = \frac{π}{8} + πn, θ = \frac{7 π}{8} + πn

Solution steps

cos (2 θ) = 2 - cos (2 θ)

Solve by substitution

cos (2 θ) = \frac{2}{2}

cos (2 θ) = \frac{2}{2} : θ = \frac{π}{8} + πn, θ = \frac{7 π}{8} + πn

Combine all the solutions

θ = \frac{π}{8} + πn, θ = \frac{7 π}{8} + πn

7 tan (x) cos (x) = 2 cos (x)

sin (4 θ) = - \frac{3}{2}

1 = 6 cos (x)

x, sec (x) = 0

sin (\frac{x}{3}) = \frac{3}{2}

What is the general solution for cos(2θ)=sqrt(2)-cos(2θ) ?
The general solution for cos(2θ)=sqrt(2)-cos(2θ) is θ= pi/8+pin,θ=(7pi)/8+pin