What is the general solution for -3sin(b)-2=sin(b)-2 ?

The general solution for -3sin(b)-2=sin(b)-2 is b=2pin,b=pi+2pin

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-3sin(b)-2=sin(b)-2

- 3 sin (b) - 2 = sin (b) - 2

b = 2 πn, b = π + 2 πn

Solution steps

- 3 sin (b) - 2 = sin (b) - 2

Solve by substitution

sin (b) = 0

sin (b) = 0 : b = 2 πn, b = π + 2 πn

Combine all the solutions

b = 2 πn, b = π + 2 πn

5 sin (2 x) = 2 cos (2 x)

tan (2 θ - 1 0^{\circ}) = cot (θ)

sinh (x) = 4

2 cos^{2} (θ) - 3 cos (θ) + 1 = 0, 0 \leq θ < 2 π

cos (x) sin (x) = 1

What is the general solution for -3sin(b)-2=sin(b)-2 ?
The general solution for -3sin(b)-2=sin(b)-2 is b=2pin,b=pi+2pin