What is the general solution for cos^2(x)-sin(x)-1=0 ?

The general solution for cos^2(x)-sin(x)-1=0 is x=(3pi)/2+2pin,x=2pin,x=pi+2pin

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cos^2(x)-sin(x)-1=0

cos^{2} (x) - sin (x) - 1 = 0

x = \frac{3 π}{2} + 2 πn, x = 2 πn, x = π + 2 πn

Solution steps

cos^{2} (x) - sin (x) - 1 = 0

Rewrite using trig identities

- sin (x) - sin^{2} (x) = 0

Solve by substitution

sin (x) = - 1, sin (x) = 0

sin (x) = - 1 : x = \frac{3 π}{2} + 2 πn

sin (x) = 0 : x = 2 πn, x = π + 2 πn

Combine all the solutions

x = \frac{3 π}{2} + 2 πn, x = 2 πn, x = π + 2 πn

5 cos (x) + 12 sin (x) = 6

- 73 tan (θ) + 5 = 26

6 sin (x) = cos (x) - 3

- 2 sin (4 x) = 0

2 sin (x) + 3 = 0, 0 \leq x \leq 2 π

What is the general solution for cos^2(x)-sin(x)-1=0 ?
The general solution for cos^2(x)-sin(x)-1=0 is x=(3pi)/2+2pin,x=2pin,x=pi+2pin