What is the general solution for -2sin(4x)=0 ?

The general solution for -2sin(4x)=0 is x=(pin)/2 ,x= pi/4+(pin)/2

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-2sin(4x)=0

- 2 sin (4 x) = 0

x = \frac{πn}{2}, x = \frac{π}{4} + \frac{πn}{2}

Solution steps

- 2 sin (4 x) = 0

Divide both sides by

- 2

sin (4 x) = 0

General solutions for

sin (4 x) = 0

4 x = 0 + 2 πn, 4 x = π + 2 πn

Solve

4 x = 0 + 2 πn : x = \frac{πn}{2}

Solve

4 x = π + 2 πn : x = \frac{π}{4} + \frac{πn}{2}

x = \frac{πn}{2}, x = \frac{π}{4} + \frac{πn}{2}

2 sin (x) + 3 = 0, 0 \leq x \leq 2 π

cos (2 x) = 1 - sin (2 x), 0 \leq x \leq 2 π

0 = 1 + 2 sin (θ)

csc (x - \frac{π}{3}) = 2

sin (θ) = \frac{11}{6}

What is the general solution for -2sin(4x)=0 ?
The general solution for -2sin(4x)=0 is x=(pin)/2 ,x= pi/4+(pin)/2