What is the general solution for tan^2(x)+2tan(x)-3=0 ?

The general solution for tan^2(x)+2tan(x)-3=0 is x= pi/4+pin,x=-1.24904…+pin

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tan^2(x)+2tan(x)-3=0

tan^{2} (x) + 2 tan (x) - 3 = 0

x = \frac{π}{4} + πn, x = - 1.24904 \dots + πn

Solution steps

tan^{2} (x) + 2 tan (x) - 3 = 0

Solve by substitution

tan (x) = 1, tan (x) = - 3

tan (x) = 1 : x = \frac{π}{4} + πn

tan (x) = - 3 : x = arctan (- 3) + πn

Combine all the solutions

x = \frac{π}{4} + πn, x = arctan (- 3) + πn

Show solutions in decimal form

x = \frac{π}{4} + πn, x = - 1.24904 \dots + πn

sin (2 x - \frac{π}{3}) = - \frac{1}{2}

2 cos (α) = 3 tan (α)

3 tan^{2} (θ) + 7 tan (θ) - 2 = - 4

8 sin (2 x) + 1 = 6

\frac{( 1 - cos ( x ) ) ( csc ^{2} ( x ) - 4 )}{1 + cos ( x )} = 0

What is the general solution for tan^2(x)+2tan(x)-3=0 ?
The general solution for tan^2(x)+2tan(x)-3=0 is x= pi/4+pin,x=-1.24904…+pin