What is the general solution for sin(3x)=0,-2<x<2 ?

The general solution for sin(3x)=0,-2<x<2 is x=0,x= pi/3 ,x=-pi/3

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sin(3x)=0,-2<x<2

sin (3 x) = 0, - 2 < x < 2

x = 0, x = \frac{π}{3}, x = - \frac{π}{3}

Solution steps

sin (3 x) = 0, - 2 < x < 2

General solutions for

sin (3 x) = 0

3 x = 0 + 2 πn, 3 x = π + 2 πn

Solve

3 x = 0 + 2 πn : x = \frac{2 πn}{3}

Solve

3 x = π + 2 πn : x = \frac{π}{3} + \frac{2 πn}{3}

x = \frac{2 πn}{3}, x = \frac{π}{3} + \frac{2 πn}{3}

Solutions for the range

- 2 < x < 2

x = 0, x = \frac{π}{3}, x = - \frac{π}{3}

tan (x) = \frac{2}{6}

2 sin^{2} (x) - 5 sin (x) = 3

cos (8 x) - cos (2 x) = sin (5 x)

tan (x) = - \frac{1}{5}

2 + 2 cos (x) = 0

What is the general solution for sin(3x)=0,-2<x<2 ?
The general solution for sin(3x)=0,-2<x<2 is x=0,x= pi/3 ,x=-pi/3